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Lay out sixteen cards as shown.
Two players alternately turn down a card and add it to the common
score, and the player who makes the score of 22, or
forces his opponent to go beyond that number, wins. For
example, A turns down a 4, B turns down a 3 (counting 7),
A turns down a 4 (counting 11), B plays a 2 (counting
13), A plays 1 (14), B plays 3 (17), and whatever A does,
B scores the winning 22 next play. Again, supposing the
play was 3-1, 1-2, 3-3, 1-2, 1-4, scoring 21, the second
player would win again, because there is no 1 left and
his opponent must go beyond 22.
Which player should always win, and how?
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